8d2-22d+9=0

Solution for 8d2-22d+9=0 equation:

8d^2-22d+9=0

a = 8; b = -22; c = +9;
Δ = b2-4ac
Δ = -222-4·8·9
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-14}{2*8}=\frac{8}{16}
=1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+14}{2*8}=\frac{36}{16}
=2+1/4
$