8c-2(c+5)=2(c-1)

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Solution for 8c-2(c+5)=2(c-1) equation: 



8c-2(c+5)=2(c-1)

We move all terms to the left:

8c-2(c+5)-(2(c-1))=0

We multiply parentheses

8c-2c-(2(c-1))-10=0



We calculate terms in parentheses: -(2(c-1)), so:

2(c-1)

We multiply parentheses

2c-2

Back to the equation:

-(2c-2)



We add all the numbers together, and all the variables

6c-(2c-2)-10=0

We get rid of parentheses

6c-2c+2-10=0

We add all the numbers together, and all the variables

4c-8=0

We move all terms containing c to the left, all other terms to the right

4c=8

c=8/4

c=2

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