8b2-7b=1-

Solution for 8b2-7b=1- equation:

8b^2-7b=1-

We move all terms to the left:

8b^2-7b-(1-)=0

We add all the numbers together, and all the variables

8b^2-7b-0=0

We add all the numbers together, and all the variables

8b^2-7b=0

a = 8; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·8·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*8}=\frac{0}{16}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*8}=\frac{14}{16}
=7/8
$