8b-2(2+3b)=2(1-2b)-3(b-1)

Solution for 8b-2(2+3b)=2(1-2b)-3(b-1) equation:

8b-2(2+3b)=2(1-2b)-3(b-1)

We move all terms to the left:

8b-2(2+3b)-(2(1-2b)-3(b-1))=0

We add all the numbers together, and all the variables

8b-2(3b+2)-(2(-2b+1)-3(b-1))=0

We multiply parentheses

8b-6b-(2(-2b+1)-3(b-1))-4=0


We calculate terms in parentheses: -(2(-2b+1)-3(b-1)), so:

2(-2b+1)-3(b-1)

We multiply parentheses

-4b-3b+2+3

We add all the numbers together, and all the variables

-7b+5

Back to the equation:

-(-7b+5)


We add all the numbers together, and all the variables

2b-(-7b+5)-4=0

We get rid of parentheses

2b+7b-5-4=0

We add all the numbers together, and all the variables

9b-9=0

We move all terms containing b to the left, all other terms to the right

9b=9

b=9/9

b=1