8a-4+10a=-10(a-5)

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Solution for 8a-4+10a=-10(a-5) equation: 



8a-4+10a=-10(a-5)

We move all terms to the left:

8a-4+10a-(-10(a-5))=0

We add all the numbers together, and all the variables

18a-(-10(a-5))-4=0



We calculate terms in parentheses: -(-10(a-5)), so:

-10(a-5)

We multiply parentheses

-10a+50

Back to the equation:

-(-10a+50)



We get rid of parentheses

18a+10a-50-4=0

We add all the numbers together, and all the variables

28a-54=0

We move all terms containing a to the left, all other terms to the right

28a=54

a=54/28

a=1+13/14

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