8a-(1-5a)=4(3a-11)-20

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Solution for 8a-(1-5a)=4(3a-11)-20 equation: 



8a-(1-5a)=4(3a-11)-20

We move all terms to the left:

8a-(1-5a)-(4(3a-11)-20)=0

We add all the numbers together, and all the variables

8a-(-5a+1)-(4(3a-11)-20)=0

We get rid of parentheses

8a+5a-(4(3a-11)-20)-1=0



We calculate terms in parentheses: -(4(3a-11)-20), so:

4(3a-11)-20

We multiply parentheses

12a-44-20

We add all the numbers together, and all the variables

12a-64

Back to the equation:

-(12a-64)



We add all the numbers together, and all the variables

13a-(12a-64)-1=0

We get rid of parentheses

13a-12a+64-1=0

We add all the numbers together, and all the variables

a+63=0

We move all terms containing a to the left, all other terms to the right

a=-63

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