8a+2(3-2a)=6(a-4)

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Solution for 8a+2(3-2a)=6(a-4) equation: 



8a+2(3-2a)=6(a-4)

We move all terms to the left:

8a+2(3-2a)-(6(a-4))=0

We add all the numbers together, and all the variables

8a+2(-2a+3)-(6(a-4))=0

We multiply parentheses

8a-4a-(6(a-4))+6=0



We calculate terms in parentheses: -(6(a-4)), so:

6(a-4)

We multiply parentheses

6a-24

Back to the equation:

-(6a-24)



We add all the numbers together, and all the variables

4a-(6a-24)+6=0

We get rid of parentheses

4a-6a+24+6=0

We add all the numbers together, and all the variables

-2a+30=0

We move all terms containing a to the left, all other terms to the right

-2a=-30

a=-30/-2

a=+15

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