8a(1+5a)=4(3a-11)-20

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Solution for 8a(1+5a)=4(3a-11)-20 equation: 



8a(1+5a)=4(3a-11)-20

We move all terms to the left:

8a(1+5a)-(4(3a-11)-20)=0

We add all the numbers together, and all the variables

8a(5a+1)-(4(3a-11)-20)=0

We multiply parentheses

40a^2+8a-(4(3a-11)-20)=0



We calculate terms in parentheses: -(4(3a-11)-20), so:

4(3a-11)-20

We multiply parentheses

12a-44-20

We add all the numbers together, and all the variables

12a-64

Back to the equation:

-(12a-64)



We get rid of parentheses

40a^2+8a-12a+64=0

We add all the numbers together, and all the variables

40a^2-4a+64=0

a = 40; b = -4; c = +64;
Δ = b2-4ac
Δ = -42-4·40·64
Δ = -10224
Delta is less than zero, so there is no solution for the equation

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