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8X(X+3)=270
We move all terms to the left:
8X(X+3)-(270)=0
We multiply parentheses
8X^2+24X-270=0
a = 8; b = 24; c = -270;
Δ = b2-4ac
Δ = 242-4·8·(-270)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-96}{2*8}=\frac{-120}{16} =-7+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+96}{2*8}=\frac{72}{16} =4+1/2 $
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