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8=8v-3/2(4v+8)
We move all terms to the left:
8-(8v-3/2(4v+8))=0
Domain of the equation: 2(4v+8))!=0We multiply all the terms by the denominator
v∈R
-(8v-3+8*2(4v+8))=0
We calculate terms in parentheses: -(8v-3+8*2(4v+8)), so:We add all the numbers together, and all the variables
8v-3+8*2(4v+8)
determiningTheFunctionDomain 8v+8*2(4v+8)-3
Wy multiply elements
8v+16v(4-3
Back to the equation:
-(8v+16v(4-3)
-(8v+16v1=0
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