8=8v+-4(1v+8)

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Solution for 8=8v+-4(1v+8) equation: 



8=8v+-4(1v+8)

We move all terms to the left:

8-(8v+-4(1v+8))=0

We add all the numbers together, and all the variables

-(8v+-4(v+8))+8=0

We use the square of the difference formula

-(8v-4(v+8))+8=0



We calculate terms in parentheses: -(8v-4(v+8)), so:

8v-4(v+8)

We multiply parentheses

8v-4v-32

We add all the numbers together, and all the variables

4v-32

Back to the equation:

-(4v-32)



We get rid of parentheses

-4v+32+8=0

We add all the numbers together, and all the variables

-4v+40=0

We move all terms containing v to the left, all other terms to the right

-4v=-40

v=-40/-4

v=+10

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