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8=5(x+6)x
We move all terms to the left:
8-(5(x+6)x)=0
We calculate terms in parentheses: -(5(x+6)x), so:We get rid of parentheses
5(x+6)x
We multiply parentheses
5x^2+30x
Back to the equation:
-(5x^2+30x)
-5x^2-30x+8=0
a = -5; b = -30; c = +8;
Δ = b2-4ac
Δ = -302-4·(-5)·8
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{265}}{2*-5}=\frac{30-2\sqrt{265}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{265}}{2*-5}=\frac{30+2\sqrt{265}}{-10} $
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