8=4+2x-(4x-3)2

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Solution for 8=4+2x-(4x-3)2 equation: 



8=4+2x-(4x-3)2

We move all terms to the left:

8-(4+2x-(4x-3)2)=0



We calculate terms in parentheses: -(4+2x-(4x-3)2), so:

4+2x-(4x-3)2

determiningTheFunctionDomain
2x-(4x-3)2+4

We multiply parentheses

2x-8x+6+4

We add all the numbers together, and all the variables

-6x+10

Back to the equation:

-(-6x+10)



We get rid of parentheses

6x-10+8=0

We add all the numbers together, and all the variables

6x-2=0

We move all terms containing x to the left, all other terms to the right

6x=2

x=2/6

x=1/3

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