8=4(2z+1)

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Solution for 8=4(2z+1) equation: 



8=4(2z+1)

We move all terms to the left:

8-(4(2z+1))=0



We calculate terms in parentheses: -(4(2z+1)), so:

4(2z+1)

We multiply parentheses

8z+4

Back to the equation:

-(8z+4)



We get rid of parentheses

-8z-4+8=0

We add all the numbers together, and all the variables

-8z+4=0

We move all terms containing z to the left, all other terms to the right

-8z=-4

z=-4/-8

z=1/2

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