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8=2/3(3x+6)
We move all terms to the left:
8-(2/3(3x+6))=0
Domain of the equation: 3(3x+6))!=0We multiply all the terms by the denominator
x∈R
-(2+8*3(3x+6))=0
We calculate terms in parentheses: -(2+8*3(3x+6)), so:We add all the numbers together, and all the variables
2+8*3(3x+6)
determiningTheFunctionDomain 8*3(3x+6)+2
Wy multiply elements
24x(3+2
Back to the equation:
-(24x(3+2)
-(24x5=0
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