8=2(10+3c)

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Solution for 8=2(10+3c) equation:



8=2(10+3c)
We move all terms to the left:
8-(2(10+3c))=0
We add all the numbers together, and all the variables
-(2(3c+10))+8=0
We calculate terms in parentheses: -(2(3c+10)), so:
2(3c+10)
We multiply parentheses
6c+20
Back to the equation:
-(6c+20)
We get rid of parentheses
-6c-20+8=0
We add all the numbers together, and all the variables
-6c-12=0
We move all terms containing c to the left, all other terms to the right
-6c=12
c=12/-6
c=-2

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