8=12b-(2b*2b)

Solution for 8=12b-(2b*2b) equation:

8=12b-(2b*2b)

We move all terms to the left:

8-(12b-(2b*2b))=0

We add all the numbers together, and all the variables

-(12b-(+2b*2b))+8=0


We calculate terms in parentheses: -(12b-(+2b*2b)), so:

12b-(+2b*2b)

We get rid of parentheses

12b-2b*2b

Wy multiply elements

-4b^2+12b

Back to the equation:

-(-4b^2+12b)


We get rid of parentheses

4b^2-12b+8=0

a = 4; b = -12; c = +8;
Δ = b2-4ac
Δ = -122-4·4·8
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4}{2*4}=\frac{8}{8}
=1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4}{2*4}=\frac{16}{8}
=2
$