8=-2(c+12)+-8

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Solution for 8=-2(c+12)+-8 equation: 



8=-2(c+12)+-8

We move all terms to the left:

8-(-2(c+12)+-8)=0

We use the square of the difference formula

-(-2(c+12)-8)+8=0



We calculate terms in parentheses: -(-2(c+12)-8), so:

-2(c+12)-8

We multiply parentheses

-2c-24-8

We add all the numbers together, and all the variables

-2c-32

Back to the equation:

-(-2c-32)



We get rid of parentheses

2c+32+8=0

We add all the numbers together, and all the variables

2c+40=0

We move all terms containing c to the left, all other terms to the right

2c=-40

c=-40/2

c=-20

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