8=(a-4)+a

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Solution for 8=(a-4)+a equation: 



8=(a-4)+a

We move all terms to the left:

8-((a-4)+a)=0



We calculate terms in parentheses: -((a-4)+a), so:

(a-4)+a

We add all the numbers together, and all the variables

a+(a-4)

We get rid of parentheses

a+a-4

We add all the numbers together, and all the variables

2a-4

Back to the equation:

-(2a-4)



We get rid of parentheses

-2a+4+8=0

We add all the numbers together, and all the variables

-2a+12=0

We move all terms containing a to the left, all other terms to the right

-2a=-12

a=-12/-2

a=+6

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