8=(X-4)(x-3)/2x-10

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Solution for 8=(X-4)(x-3)/2x-10 equation: 


x in (-oo:+oo)

8 = x*(((X-4)*(x-3))/2)-10 // - x*(((X-4)*(x-3))/2)-10

8-(x*(((X-4)*(x-3))/2))+10 = 0

(-1*x*(X-4)*(x-3))/2+8+10 = 0

(-1*x*(X-4)*(x-3))/2+(2*8)/2+(2*10)/2 = 0

2*8-1*x*(X-4)*(x-3)+2*10 = 0

3*X*x-(X*x^2)+4*x^2-12*x+16+20 = 0

3*X*x-(X*x^2)+4*x^2-12*x+36 = 0

3*X*x-(X*x^2)+4*x^2-12*x+36 = 0

4*x^2-12*x+36 = 0

DELTA = (-12)^2-(4*4*36)

DELTA = -432

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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