8=(3/4)(5x+20)

Solution for 8=(3/4)(5x+20) equation:

8=(3/4)(5x+20)

We move all terms to the left:

8-((3/4)(5x+20))=0


Domain of the equation: 4)(5x+20))!=0

x∈R


We add all the numbers together, and all the variables

-((+3/4)(5x+20))+8=0

We multiply parentheses ..

-((+15x^2+3/4*20))+8=0

We multiply all the terms by the denominator


-((+15x^2+3+8*4*20))=0


We calculate terms in parentheses: -((+15x^2+3+8*4*20)), so:

(+15x^2+3+8*4*20)

We get rid of parentheses

15x^2+3+8*4*20

We add all the numbers together, and all the variables

15x^2+643

Back to the equation:

-(15x^2+643)


We get rid of parentheses

-15x^2-643=0

a = -15; b = 0; c = -643;
Δ = b2-4ac
Δ = 02-4·(-15)·(-643)
Δ = -38580
Delta is less than zero, so there is no solution for the equation