8=(2(x+5)-6)/2

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Solution for 8=(2(x+5)-6)/2 equation: 



8=(2(x+5)-6)/2

We move all terms to the left:

8-((2(x+5)-6)/2)=0

We multiply all the terms by the denominator


-((2(x+5)-6)+8*2)=0



We calculate terms in parentheses: -((2(x+5)-6)+8*2), so:

(2(x+5)-6)+8*2

We add all the numbers together, and all the variables

(2(x+5)-6)+16



We calculate terms in parentheses: +(2(x+5)-6), so:

2(x+5)-6

We multiply parentheses

2x+10-6

We add all the numbers together, and all the variables

2x+4

Back to the equation:

+(2x+4)



We get rid of parentheses

2x+4+16

We add all the numbers together, and all the variables

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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