8=(1/4t)-3

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Solution for 8=(1/4t)-3 equation: 



8=(1/4t)-3

We move all terms to the left:

8-((1/4t)-3)=0



Domain of the equation: 4t)-3)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

-((+1/4t)-3)+8=0

We multiply all the terms by the denominator


-((+1+8*4t)-3)=0



We calculate terms in parentheses: -((+1+8*4t)-3), so:

(+1+8*4t)-3

We add all the numbers together, and all the variables

(8*4t+1)-3

We get rid of parentheses

8*4t+1-3

We add all the numbers together, and all the variables

8*4t-2

Wy multiply elements

32t-2

Back to the equation:

-(32t-2)



We get rid of parentheses

-32t+2=0

We move all terms containing t to the left, all other terms to the right

-32t=-2

t=-2/-32

t=1/16

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