If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4*x^3+4*x^2+0*x^4+0*x+0 = 0;x
x
3207;9
11.60145;29
1;352;1;445;0;0
390.4;16
| 4(1-2x)-(5x+1)=8+3(x-3)+12(2-3x) | | 4y-3y=10 | | y=in(x-1)+2 | | -y/4=-35 | | 12t-7t=10 | | 2+3x^2+20x^4=0 | | 38=8-2 | | 17=4x-2x+1 | | -25=w/3 | | 2(-1)-y=-1 | | 3cos^2x*sinx-1=0 | | f(3)f(x)=2x^2+5 | | 4sin^2x=3cos^2x | | 6(2x-1)=2(6x+2) | | -0.75x-0=-3 | | 8(x-2)=19 | | 2t^2+2t+1=0 | | 16/(8-4) | | 3s(a+7)=51 | | Log[b]m=y | | 3.3-6.7n=11 | | 4-2x/3=3/4-5z/6 | | 2p+38=6p-14 | | 2(4)+3y=11 | | 4t-6=90-2t | | 12x-3/4=120 | | 4*.346/(-2*.346+12*.534+3)= | | 2(-3)+3y=11 | | 2(3)+3y=11 | | 6(x+1)-2(2x+3)=10-22x-12(x-1)+3x | | X-0.25=0.25(-2x-5)+1.5(x-1) | | 2(-2)+3y=11 |