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85=w(w+13)
We move all terms to the left:
85-(w(w+13))=0
We calculate terms in parentheses: -(w(w+13)), so:We get rid of parentheses
w(w+13)
We multiply parentheses
w^2+13w
Back to the equation:
-(w^2+13w)
-w^2-13w+85=0
We add all the numbers together, and all the variables
-1w^2-13w+85=0
a = -1; b = -13; c = +85;
Δ = b2-4ac
Δ = -132-4·(-1)·85
Δ = 509
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{509}}{2*-1}=\frac{13-\sqrt{509}}{-2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{509}}{2*-1}=\frac{13+\sqrt{509}}{-2} $
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