832=(2)(x-4)(x+6)

Solution for 832=(2)(x-4)(x+6) equation:

832=(2)(x-4)(x+6)

We move all terms to the left:

832-((2)(x-4)(x+6))=0

We multiply parentheses ..

-(2(+x^2+6x-4x-24))+832=0


We calculate terms in parentheses: -(2(+x^2+6x-4x-24)), so:

2(+x^2+6x-4x-24)

We multiply parentheses

2x^2+12x-8x-48

We add all the numbers together, and all the variables

2x^2+4x-48

Back to the equation:

-(2x^2+4x-48)


We get rid of parentheses

-2x^2-4x+48+832=0

We add all the numbers together, and all the variables

-2x^2-4x+880=0

a = -2; b = -4; c = +880;
Δ = b2-4ac
Δ = -42-4·(-2)·880
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-84}{2*-2}=\frac{-80}{-4}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+84}{2*-2}=\frac{88}{-4}
=-22
$