81x2+180x+100=0

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Solution for 81x2+180x+100=0 equation: 



81x^2+180x+100=0

a = 81; b = 180; c = +100;
Δ = b2-4ac
Δ = 1802-4·81·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-180}{162}=-1+1/9$

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