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81=x(3+x)
We move all terms to the left:
81-(x(3+x))=0
We add all the numbers together, and all the variables
-(x(x+3))+81=0
We calculate terms in parentheses: -(x(x+3)), so:We get rid of parentheses
x(x+3)
We multiply parentheses
x^2+3x
Back to the equation:
-(x^2+3x)
-x^2-3x+81=0
We add all the numbers together, and all the variables
-1x^2-3x+81=0
a = -1; b = -3; c = +81;
Δ = b2-4ac
Δ = -32-4·(-1)·81
Δ = 333
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{333}=\sqrt{9*37}=\sqrt{9}*\sqrt{37}=3\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{37}}{2*-1}=\frac{3-3\sqrt{37}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{37}}{2*-1}=\frac{3+3\sqrt{37}}{-2} $
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