81=b-6(1+5b)

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Solution for 81=b-6(1+5b) equation: 



81=b-6(1+5b)

We move all terms to the left:

81-(b-6(1+5b))=0

We add all the numbers together, and all the variables

-(b-6(5b+1))+81=0



We calculate terms in parentheses: -(b-6(5b+1)), so:

b-6(5b+1)

We multiply parentheses

b-30b-6

We add all the numbers together, and all the variables

-29b-6

Back to the equation:

-(-29b-6)



We get rid of parentheses

29b+6+81=0

We add all the numbers together, and all the variables

29b+87=0

We move all terms containing b to the left, all other terms to the right

29b=-87

b=-87/29

b=-3

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