81+2=4(4j+6)-5

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Solution for 81+2=4(4j+6)-5 equation: 



81+2=4(4j+6)-5

We move all terms to the left:

81+2-(4(4j+6)-5)=0

We add all the numbers together, and all the variables

-(4(4j+6)-5)+83=0



We calculate terms in parentheses: -(4(4j+6)-5), so:

4(4j+6)-5

We multiply parentheses

16j+24-5

We add all the numbers together, and all the variables

16j+19

Back to the equation:

-(16j+19)



We get rid of parentheses

-16j-19+83=0

We add all the numbers together, and all the variables

-16j+64=0

We move all terms containing j to the left, all other terms to the right

-16j=-64

j=-64/-16

j=+4

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