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80x^2+92x-84=0
a = 80; b = 92; c = -84;
Δ = b2-4ac
Δ = 922-4·80·(-84)
Δ = 35344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{35344}=188$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-188}{2*80}=\frac{-280}{160} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+188}{2*80}=\frac{96}{160} =3/5 $
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