80x-10(3-4x)=54+6(x-7)

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Solution for 80x-10(3-4x)=54+6(x-7) equation: 



80x-10(3-4x)=54+6(x-7)

We move all terms to the left:

80x-10(3-4x)-(54+6(x-7))=0

We add all the numbers together, and all the variables

80x-10(-4x+3)-(54+6(x-7))=0

We multiply parentheses

80x+40x-(54+6(x-7))-30=0



We calculate terms in parentheses: -(54+6(x-7)), so:

54+6(x-7)

determiningTheFunctionDomain
6(x-7)+54

We multiply parentheses

6x-42+54

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

120x-(6x+12)-30=0

We get rid of parentheses

120x-6x-12-30=0

We add all the numbers together, and all the variables

114x-42=0

We move all terms containing x to the left, all other terms to the right

114x=42

x=42/114

x=7/19

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