80=2(2x+5)+(x-10)

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Solution for 80=2(2x+5)+(x-10) equation: 



80=2(2x+5)+(x-10)

We move all terms to the left:

80-(2(2x+5)+(x-10))=0



We calculate terms in parentheses: -(2(2x+5)+(x-10)), so:

2(2x+5)+(x-10)

We multiply parentheses

4x+(x-10)+10

We get rid of parentheses

4x+x-10+10

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



We move all terms containing x to the left, all other terms to the right

-5x=-80

x=-80/-5

x=+16

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