80=-8(4y+2)

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Solution for 80=-8(4y+2) equation: 



80=-8(4y+2)

We move all terms to the left:

80-(-8(4y+2))=0



We calculate terms in parentheses: -(-8(4y+2)), so:

-8(4y+2)

We multiply parentheses

-32y-16

Back to the equation:

-(-32y-16)



We get rid of parentheses

32y+16+80=0

We add all the numbers together, and all the variables

32y+96=0

We move all terms containing y to the left, all other terms to the right

32y=-96

y=-96/32

y=-3

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