80-(4x+6)=4(x+5)+x

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Solution for 80-(4x+6)=4(x+5)+x equation: 



80-(4x+6)=4(x+5)+x

We move all terms to the left:

80-(4x+6)-(4(x+5)+x)=0

We get rid of parentheses

-4x-(4(x+5)+x)-6+80=0



We calculate terms in parentheses: -(4(x+5)+x), so:

4(x+5)+x

We add all the numbers together, and all the variables

x+4(x+5)

We multiply parentheses

x+4x+20

We add all the numbers together, and all the variables

5x+20

Back to the equation:

-(5x+20)



We add all the numbers together, and all the variables

-4x-(5x+20)+74=0

We get rid of parentheses

-4x-5x-20+74=0

We add all the numbers together, and all the variables

-9x+54=0

We move all terms containing x to the left, all other terms to the right

-9x=-54

x=-54/-9

x=+6

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