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80+x+x+1/3x=570
We move all terms to the left:
80+x+x+1/3x-(570)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2x+1/3x-490=0
We multiply all the terms by the denominator
2x*3x-490*3x+1=0
Wy multiply elements
6x^2-1470x+1=0
a = 6; b = -1470; c = +1;
Δ = b2-4ac
Δ = -14702-4·6·1
Δ = 2160876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2160876}=\sqrt{4*540219}=\sqrt{4}*\sqrt{540219}=2\sqrt{540219}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1470)-2\sqrt{540219}}{2*6}=\frac{1470-2\sqrt{540219}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1470)+2\sqrt{540219}}{2*6}=\frac{1470+2\sqrt{540219}}{12} $
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