80+(4x)=128

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Solution for 80+(4x)=128 equation: 



80+(4x)=128

We move all terms to the left:

80+(4x)-(128)=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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