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8/x=5/2x+11
We move all terms to the left:
8/x-(5/2x+11)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+11)!=0We get rid of parentheses
x∈R
8/x-5/2x-11=0
We calculate fractions
16x/2x^2+(-5x)/2x^2-11=0
We multiply all the terms by the denominator
16x+(-5x)-11*2x^2=0
Wy multiply elements
-22x^2+16x+(-5x)=0
We get rid of parentheses
-22x^2+16x-5x=0
We add all the numbers together, and all the variables
-22x^2+11x=0
a = -22; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-22)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-22}=\frac{-22}{-44} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-22}=\frac{0}{-44} =0 $
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