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8/x=3/3x+2
We move all terms to the left:
8/x-(3/3x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+2)!=0We get rid of parentheses
x∈R
8/x-3/3x-2=0
We calculate fractions
24x/3x^2+(-3x)/3x^2-2=0
We multiply all the terms by the denominator
24x+(-3x)-2*3x^2=0
Wy multiply elements
-6x^2+24x+(-3x)=0
We get rid of parentheses
-6x^2+24x-3x=0
We add all the numbers together, and all the variables
-6x^2+21x=0
a = -6; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-6)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-6}=\frac{-42}{-12} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-6}=\frac{0}{-12} =0 $
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