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8/x+8/2x=4
We move all terms to the left:
8/x+8/2x-(4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
16x/2x^2+8x/2x^2-4=0
We multiply all the terms by the denominator
16x+8x-4*2x^2=0
We add all the numbers together, and all the variables
24x-4*2x^2=0
Wy multiply elements
-8x^2+24x=0
a = -8; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-8)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-8}=\frac{-48}{-16} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-8}=\frac{0}{-16} =0 $
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