If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((cos(x))^2)^(1/2)*cos((x^2+1)^(1/2))
n+1;n-1;n-1;n-3;0;0
1/6-7 = 2
5;7;21;10;2;0
2800;2679
| x+25+3x+2x+35+x+20= | | 9(2x-8)=5x-7 | | x^2-4x-17=y | | 1/6-7=2 | | 7m-4=3 | | 247=(x-6)*x | | x=2xy+2 | | ht=-.16t^2+40t+0 | | 54x+9y-36=0 | | 6:(9/6) | | ht=-.5(g)t^2+40t+0 | | 100*20=2xyz | | 36x=30x+30 | | x+13=100 | | x*y=12 | | ht=-.5(g)t^2+40t+h | | 3/8=z/16 | | X+5x=.5 | | x^4+2x^3+5x^2+6x+9=0 | | r/0.5=2 | | (gx)=x^2-10x-3 | | T/0.16=0.7 | | cos34=20/x | | 2x^5+32x^3-944x=0 | | 0=3t^3-8t^2+7t-2 | | (5x)*1/3 | | 3p+2=1-(2p-4) | | 8x+4y=-13 | | (1/3)*1/3 | | (1/3)x1/3 | | 12x^3-12x^2-72x=0 | | 7x+2=-10 |