8/9(3t+27)=2/9t+68

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Solution for 8/9(3t+27)=2/9t+68 equation: 



8/9(3t+27)=2/9t+68

We move all terms to the left:

8/9(3t+27)-(2/9t+68)=0



Domain of the equation: 9(3t+27)!=0

t∈R





Domain of the equation: 9t+68)!=0

t∈R



We get rid of parentheses

8/9(3t+27)-2/9t-68=0

We calculate fractions


72t/(243t^2+2187t)+(-18t3/(243t^2+2187t)-68=0

We calculate fractions

We do not support etpression: t^3

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