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8/6x-4x=1
We move all terms to the left:
8/6x-4x-(1)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
-4x+8/6x-1=0
We multiply all the terms by the denominator
-4x*6x-1*6x+8=0
Wy multiply elements
-24x^2-6x+8=0
a = -24; b = -6; c = +8;
Δ = b2-4ac
Δ = -62-4·(-24)·8
Δ = 804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{804}=\sqrt{4*201}=\sqrt{4}*\sqrt{201}=2\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{201}}{2*-24}=\frac{6-2\sqrt{201}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{201}}{2*-24}=\frac{6+2\sqrt{201}}{-48} $
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