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8/5x+8/10x=45/15
We move all terms to the left:
8/5x+8/10x-(45/15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
8/5x+8/10x-3=0
We calculate fractions
80x/50x^2+40x/50x^2-3=0
We multiply all the terms by the denominator
80x+40x-3*50x^2=0
We add all the numbers together, and all the variables
120x-3*50x^2=0
Wy multiply elements
-150x^2+120x=0
a = -150; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·(-150)·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*-150}=\frac{-240}{-300} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*-150}=\frac{0}{-300} =0 $
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