8/5=(4x+4)/2x

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Solution for 8/5=(4x+4)/2x equation: 



8/5=(4x+4)/2x

We move all terms to the left:

8/5-((4x+4)/2x)=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(-((4x+4)*5)/2x*5)+16x/2x*5)=0



We calculate terms in parentheses: +(-((4x+4)*5)/2x*5), so:

-((4x+4)*5)/2x*5

We multiply all the terms by the denominator


-((4x+4)*5)



We calculate terms in parentheses: -((4x+4)*5), so:

(4x+4)*5

We multiply parentheses

20x+20

Back to the equation:

-(20x+20)



We get rid of parentheses

-20x-20

Back to the equation:

+(-20x-20)



We get rid of parentheses

-20x+16x/2x*5)-20=0

We multiply all the terms by the denominator


-20x*2x*5)-20+16x=0

Wy multiply elements

-200x^3*5=0

We do not support expression: x^3

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