8/3y+7=5y

Solution for 8/3y+7=5y equation:

8/3y+7=5y

We move all terms to the left:

8/3y+7-(5y)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

-5y+8/3y+7=0

We multiply all the terms by the denominator


-5y*3y+7*3y+8=0

Wy multiply elements

-15y^2+21y+8=0

a = -15; b = 21; c = +8;
Δ = b2-4ac
Δ = 212-4·(-15)·8
Δ = 921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{921}}{2*-15}=\frac{-21-\sqrt{921}}{-30}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{921}}{2*-15}=\frac{-21+\sqrt{921}}{-30}
$