8/3c-2=2/4c-12

Solution for 8/3c-2=2/4c-12 equation:

8/3c-2=2/4c-12

We move all terms to the left:

8/3c-2-(2/4c-12)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 4c-12)!=0

c∈R


We get rid of parentheses

8/3c-2/4c+12-2=0

We calculate fractions


32c/12c^2+(-6c)/12c^2+12-2=0

We add all the numbers together, and all the variables

32c/12c^2+(-6c)/12c^2+10=0

We multiply all the terms by the denominator


32c+(-6c)+10*12c^2=0

Wy multiply elements

120c^2+32c+(-6c)=0

We get rid of parentheses

120c^2+32c-6c=0

We add all the numbers together, and all the variables

120c^2+26c=0

a = 120; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·120·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*120}=\frac{-52}{240}
=-13/60
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*120}=\frac{0}{240}
=0
$