8/3=(n-7)/6

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Solution for 8/3=(n-7)/6 equation: 



8/3=(n-7)/6

We move all terms to the left:

8/3-((n-7)/6)=0

We calculate fractions


(-((n-7)*3)/()+()/()=0



We calculate terms in parentheses: +(-((n-7)*3)/()+()/(), so:

-((n-7)*3)/()+()/(

We add all the numbers together, and all the variables

-((n-7)*3)/()+1

We multiply all the terms by the denominator


-((n-7)*3)+1*()



We calculate terms in parentheses: -((n-7)*3), so:

(n-7)*3

We multiply parentheses

3n-21

Back to the equation:

-(3n-21)



We add all the numbers together, and all the variables

-(3n-21)

We get rid of parentheses

-3n+21

Back to the equation:

+(-3n+21)



We get rid of parentheses

-3n+21=0

We move all terms containing n to the left, all other terms to the right

-3n=-21

n=-21/-3

n=+7

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