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8/33c-2=2/3c-12
We move all terms to the left:
8/33c-2-(2/3c-12)=0
Domain of the equation: 33c!=0
c!=0/33
c!=0
c∈R
Domain of the equation: 3c-12)!=0We get rid of parentheses
c∈R
8/33c-2/3c+12-2=0
We calculate fractions
24c/99c^2+(-66c)/99c^2+12-2=0
We add all the numbers together, and all the variables
24c/99c^2+(-66c)/99c^2+10=0
We multiply all the terms by the denominator
24c+(-66c)+10*99c^2=0
Wy multiply elements
990c^2+24c+(-66c)=0
We get rid of parentheses
990c^2+24c-66c=0
We add all the numbers together, and all the variables
990c^2-42c=0
a = 990; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·990·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*990}=\frac{0}{1980} =0 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*990}=\frac{84}{1980} =7/165 $
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