8/12x+4/2=3/6x+4

Solution for 8/12x+4/2=3/6x+4 equation:

8/12x+4/2=3/6x+4

We move all terms to the left:

8/12x+4/2-(3/6x+4)=0


Domain of the equation: 12x!=0

x!=0/12

x!=0

x∈R



Domain of the equation: 6x+4)!=0

x∈R


We add all the numbers together, and all the variables

8/12x-(3/6x+4)+2=0

We get rid of parentheses

8/12x-3/6x-4+2=0

We calculate fractions


48x/72x^2+(-36x)/72x^2-4+2=0

We add all the numbers together, and all the variables

48x/72x^2+(-36x)/72x^2-2=0

We multiply all the terms by the denominator


48x+(-36x)-2*72x^2=0

Wy multiply elements

-144x^2+48x+(-36x)=0

We get rid of parentheses

-144x^2+48x-36x=0

We add all the numbers together, and all the variables

-144x^2+12x=0

a = -144; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-144)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-144}=\frac{-24}{-288}
=1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-144}=\frac{0}{-288}
=0
$